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18-11-2018
Chemistry

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An 8.50 L tire contains .552 lol of gas at a temperature of 305 K. What's the pressure , in atm and in psi, of the gas in the tire?

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malika8888 malika8888

18-11-2018

PV=nRT
P×8.5=0.552×0.082×305
8.5P=13,80552
[tex]PV=nRT \\
P×8.5=0.552×0.082×305 \\
8.5P=13,80552 \\ P = \frac{13,80552}{8.5} \\ P = 1.6 \: atm[/tex]

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