[tex]27)\\sine=\dfrac{opposite}{hypotenuse}\\\\\text{We have:}\\opposite=40\\hypotenuse=50\\\\\sin C=\dfrac{40}{50}=\dfrac{4}{5}\\\\29)\\\\tangent=\dfrac{opposite}{adjacent}\\\text{We have:}\\opposite=18\\adjacent=24\\\\\tan C=\dfrac{18}{24}=\dfrac{18:6}{24:6}=\dfrac{3}{4}[/tex]
