qveenchantell
qveenchantell
18-10-2018
Mathematics
contestada
4(r+20)=1/5 (20r +400)
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konrad509
konrad509
18-10-2018
[tex]4(r+20)=\dfrac{1}{5}(20r+400)\\\\4r+80=4r+80\\\\0=0\\\\r\in\mathbb{R}[/tex]
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