kittykatnat7469 kittykatnat7469

18-10-2018
Mathematics

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What is the answer to the problem 3(2x-5)-4(x-3)=7

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Аноним Аноним

18-10-2018

Disitribute the 3 to the first parenthesis:

[tex] 3(2x-5) = 6x-15 [/tex]

Distribute the 4 to the second parenthesis:

[tex] 4(x-3)=4x-12 [/tex]

So, the equation becomes

[tex] 6x-15-4x+12=7 \iff 2x=10 \iff x = \dfrac{10}{2} = 5 [/tex]

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