naviyharichardson naviyharichardson

17-10-2018
Mathematics

contestada

is the square root of 2+1 greater or less than or equal to the square root of 2+2

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mathstudent55 mathstudent55

17-10-2018

Answer:

[tex] \sqrt{2 + 1} < \sqrt{2 + 2} [/tex]

Step-by-step explanation:

[tex] \sqrt{2 + 1} = \sqrt{3} = 1.73205... [/tex]

[tex] \sqrt{2 + 2} = \sqrt{4} = 2 [/tex]

Since [tex] 1.73205... < 2 [/tex], then

[tex] \sqrt{2 + 1} < \sqrt{2 + 2} [/tex]

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