Answer:
[tex]y\leq 3[/tex]
All real numbers less than or equal to 3
Step-by-step explanation:
we have
[tex]3y\leq 2y+3[/tex]
Solve for y
Subtract 2y both sides
[tex]3y-2y\leq 2y+3-2y[/tex]
[tex]y\leq 3[/tex]
The solution is the interval ------> (-∞,3]
All real numbers less than or equal to 3
In a number line the solution is the shaded area down of y=3 (close circle)
see the attached figure
