nevaehhamilton nevaehhamilton

20-09-2018
Mathematics

contestada

Solve x3 = 1 over 8.
1 over 2
±1 over 2
1 over 4
±1 over 4

Respuesta :

jdoe0001 jdoe0001

20-09-2018

[tex]\bf x^3=\cfrac{1}{8}\implies \sqrt[3]{x^3}=\sqrt[3]{\cfrac{1}{8}}\implies x=\sqrt[3]{\cfrac{1}{8}}\implies x=\cfrac{\sqrt[3]{1}}{\sqrt[3]{8}} \\\\\\ x=\cfrac{\sqrt[3]{1^3}}{\sqrt[3]{2^3}}\implies x=\cfrac{1}{2}[/tex]

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