Tatiiii116 Tatiiii116

20-09-2018
Mathematics

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if d is the midpoint of CE, CD=X+7,AND CE=5×-1 DETERMINE EACH MISSING VALUE

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Аноним Аноним

20-09-2018

The midpoint splits a segment in two sub-segments of equal length. This means that CD and DE are both half of CE

So, you have

[tex] CE = 2CD [/tex]

Plug in the expressions you're given:

[tex] 5x-1 = 2(x+7) \iff 5x-1 = 2x + 14 \iff 3x = 15 \iff x = 5 [/tex]

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