Answer:
Option b is correct
g(f(3)-2f(1)) =0
Step-by-step explanation:
Given the functions:
[tex]g(t) = t^2-t[/tex]
and
[tex]f(x) = 1+x[/tex]
We have to find g(f(3)-2f(1)) .
At x = 3
[tex]f(3) = 1+3 = 4[/tex]
at x = 1
[tex]f(1) = 1+1= 2[/tex]
then;
g(f(3)-2f(1)) = [tex]g(4-2(2)) = g(4-4) = g(0)[/tex]
then;
[tex]g(f(3)-2f(1)) = 0^2-0 = 0[/tex]
Therefore, the indicated value of [tex]g(f(3)-2f(1)) [/tex] is , 0
