chayiljacquet
chayiljacquet chayiljacquet
  • 20-07-2018
  • Mathematics
contestada

Normal form problem [see attachment]

Normal form problem see attachment class=

Respuesta :

DeanR
DeanR DeanR
  • 20-07-2018

I'm not familiar with the notation but I'll guess this refers to the equation:


[tex] p = x \cos \phi + y \sin \phi [/tex]


[tex] 11\pi/6 [/tex] is -30 degrees


[tex] 4 \sqrt{3} = x (\sqrt{3}/2) - y/2 [/tex]


[tex] \sqrt{3} x - y - 8 \sqrt{3} = 0 [/tex]


Choice b



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