If f(x)=-x^2+6x-1 and g(x)=3x^2-4x-1, find (f-g)(x)
f(x) = - x^2 + 6x -1
and
g(x)=3x^2 - 4x - 1
(f-g)(x) = - x^2 + 6x -1 -(3x^2 - 4x - 1)
(f-g)(x) = - x^2 + 6x -1 - 3x^2 + 4x + 1
(f-g)(x) = - 4x^2 + 10x
Answer is A.
(f-g)(x) = - 4x^2 + 10x