7P6/7P4 Simplify the expression. 14, 840, 6, or 5,040 ?
[tex] \dfrac{_7P_6}{_7P_4}=\dfrac{\dfrac{7!}{1!}}{\dfrac{7!}{3!}}=\dfrac{7!}{4\cdot5\cdot6\cdot7}=\dfrac{2\cdot3\cdot4\cdot5\cdot6\cdot7}{4\cdot5\cdot6\cdot7}=2\cdot3=6 [/tex]