Respuesta :

superman1987
when ΔH = -445.1 KJ/mol (given) missing in your question.

and this value is per mole NaOH.

∴ the amount of heat = ΔH / mol NaOH * (mass NaOH) (1 mol NaOH / molar mass NaOH)

by substitution:

                                   = -445.1 KJ/mol / mol NaOH * 1 g NaOH * 1molNaOH                                         /40 g NaOH

                                  = -11.1 KJ

Otras preguntas