The first thing to do is find the percentage of number of players with no defects.
 For this, we make the following rule of three:
 500 --------> 100%
 496 --------> x
 Clearing x we have:
 x = (496/500) * (100)
 x = 99.2%
 Then, for 2000 video players we have:
 (2000) * (0.992) = 1984
 Answer:
 The number of players in the shipment that are likely to have no defects are:
 1984