Respuesta :

jushmk
If;
A = Adjacent
O = Opposite
H = Hypotenuse

Then,
Sin Ф = O/H
Cos Ф = A/H
Therefore,
(Sin Ф)/Cos Ф) = (O/H)/(A/H) = (O/H)*(H/A) = O/A

Now,
tan Ф = O/A ----

Therefore, it is true that
tan Ф = SinФ/CosФ
CastleRook
Take a right angled triangle  with side lengths x, y, and z, where x is the hypotenuse.
sin θ=z/x
cos θ=y/x
sinθ/cosθ=(z/x)/(y/x)=z/y=tan θ
the statement is true.

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