which shows how to find the value of this expression when x=-2 and y=5? (3x^3y^-2)^2

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16-05-2018
Mathematics

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which shows how to find the value of this expression when x=-2 and y=5? (3x^3y^-2)^2

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Professor1994 Professor1994 · Answer 1 · 2018-05-16T04:43:17+02:00

Professor1994 Professor1994

16-05-2018

x=-2 and y=5

(3x^3y^-2)^2=[3(-2)^3 (5)^(-2)]^2=[3(-8)/(5)^2]^2=(-24/25)^2=(-24)^2/(25)^2

(3x^3y^-2)^2=576/625

Answer: The value of the expression is 576/625

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Lunargarcia0 Lunargarcia0 · Answer 2 · 2020-11-30T21:13:41+01:00

Lunargarcia0 Lunargarcia0

30-11-2020

Answer:

Option 1 - 32(-2)6/54

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