In order to calculate the specific heat of the unknown metal (Smetal), we assumed that all of the heat
released by the hot metal went into raising the temperature of
the cool water. If some of that heat
actually went into raising the temperature of the calorimeter cup,
the lid, or the surrounding air
instead
of the cool water, the calculated
Smetal
value would be incorrect. Would the calculated value
be too high
or too low? Explain your answer.