Em4i1lynBonnas
Em4i1lynBonnas
19-11-2016
Mathematics
contestada
integrate sin^43x dx
Respuesta :
syed514
syed514
20-11-2016
sstarica the question is
∫
sin4
3x dx
substitute (cos x)^2 = 1 - (sin x)^2
∫(1−
cos^2
(3x)
)^2
dx = ∫(1−2
cos^2
u +
cos^2
u) d
u
1/15
∫ 5(3)
sin^4
(3x) d
x
=
-cos^5 (3x)/15 + C
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